# Analyse:Mac/Fragment 011 22

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 Typus KomplettPlagiat Bearbeiter Graf Isolan Gesichtet
Untersuchte Arbeit:
Seite: 11, Zeilen: 22-32
Quelle: Thomsen 2007
Seite(n): 13, Zeilen: 13-23
Bosons and fermions provide corrections to the Higgs mass with a different sign. If one postulates a partner for each particle, which differs by 1/2 unit in spin, but otherwise has the same quantum numbers, this performs an automatic cancellation of the form

$\delta m^2_H = - \frac{\lambda_F^2}{16\pi^2} (\Lambda;^2+m_F^2) + \frac{\lambda_F^2}{16\pi^2} (\Lambda;^2+m_B^2) + \dots = {\mathcal O} (\frac{\alpha}{4\pi})\vert m_B^2 - m_F^2\vert, \quad \quad (2.25)$

Assuming the Yukawa couplings for fermions and bosons to be equal F = λB). This reduces the corrections to an acceptable level, as long as the masses do not differ much more than about a TeV. The fine tuning and Hierarchy problem, explained before, can therefore be handled in an elegant way. According to this argument Supersymmetric partners of the SM particles should not to be too heavy and can be found at LHC energies.

Bosons and fermions enter the corrections to the Higgs mass with a different sign. If one postulates a partner for each particle, which differs by 1/2 unit in spin, but otherwise has the same quantum numbers, this performs an automatic cancellation of the form:

$\delta m^2_H = - \frac{\lambda_F^2}{16\pi^2} (\Lambda;^2+m_F^2) + \frac{\lambda_F^2}{16\pi^2} (\Lambda;^2+m_B^2) + \dots = {\mathcal O} (\frac{\alpha}{4\pi})\vert m_B^2 - m_F^2\vert, \quad \quad (3.1)$

assuming the Yukawa couplings for fermions and bosons to be equal F = λB). This reduces the corrections to an acceptable level, as long as the masses do not differ much more than about a TeV. The fine tuning problem can therefore be avoided in an elegant way and as supersymmetric partners should not be too heavy there is a good chance to find supersymmetry with the LHC with a center of mass energy of 14 TeV.

 Anmerkungen Ohne Hinweis auf eine Übernahme. Sichter (Graf Isolan)